PERIMETER & AREA
PERIMETER & AREA: THE MATHEMATICS OF SPACE
π Introduction: Why Do We Need Perimeter and Area?
Imagine you want to fence your garden, paint your house walls, or buy a carpet for your room. You need to measure how much material is required. Perimeter helps in measuring the boundary, while area tells us how much space is covered.
π Memory Trick:
β Perimeter = Path around (fencing, boundary)
β Area = Space inside (paint, carpet, land)
π€οΈ What is Perimeter?
π Definition: Perimeter is the total length of the boundary of a closed shape.
π Formula:
Perimeter=Sum of all sides\text{Perimeter} = \text{Sum of all sides}Perimeter=Sum of all sides
πΈ Perimeter Formulas of Common Shapes
|
Shape |
Formula |
Example |
|
Square |
P=4Γside |
Side = 5 cm β P = 4 Γ 5 = 20 cm |
|
Rectangle |
P=2(l+b) |
l = 8 cm, b = 4 cm β P = 2(8+4) = 24 cm |
|
Triangle |
P=a+b+c |
a = 3 cm, b = 4 cm, c = 5 cm β P = 3+4+5 = 12 cm |
|
Circle (Circumference) |
C=2Οr |
r = 7 cm β C β 2 Γ 3.14 Γ 7 = 44 cm |
π Shortcut for Regular Shapes:
β If all sides are equal, just multiply by the number of sides!
ποΈ What is Area?
π Definition: Area is the amount of surface covered by a shape.
π Formula:
Area=Space inside the boundary\text{Area} = \text{Space inside the boundary}Area=Space inside the boundary
πΉ Area Formulas of Common Shapes
|
Shape |
Formula |
Example |
|
Square |
A=side^2 |
Side = 6 cm β A = 6Β² = 36 cmΒ² |
|
Rectangle |
A=lΓb |
l = 7 cm, b = 4 cm β A = 7 Γ 4 = 28 cmΒ² |
|
Triangle |
A=1/2Γ(bΓh) |
b = 10 cm, h = 6 cm β A = Β½ Γ 10 Γ 6 = 30 cmΒ² |
|
Circle |
A=Οr^2 |
r = 5 cm β A β 3.14 Γ 5Β² = 78.5 cmΒ² |
π Quick Trick:
β Square = side Γ side
β Rectangle = length Γ breadth
β Triangle = Β½ Γ base Γ height
β Circle = Ο Γ radiusΒ²
π‘ Real-Life Applications of Perimeter and Area
β
Garden Fence: To find the fence length, calculate perimeter.
β
Painting Walls: To find how much paint is needed, calculate area.
β
Buying Tiles or Carpets: To cover a floor, measure area.
β
Running Tracks: To know how much you run, find the perimeter of the track.
π How to Find Perimeter and Area of Complex Shapes?
1οΈβ£ Composite Figures (Combination of Shapes)
Example: Find the area of an L-shaped figure
1οΈβ£ Divide it into smaller rectangles.
2οΈβ£ Find the area of each rectangle.
3οΈβ£ Add them together to get the total area.
2οΈβ£ Finding the Shaded Region
Example: A circular field with a square garden inside
1οΈβ£ Find the area of the circle.
2οΈβ£ Find the area of the square.
3οΈβ£ Subtract squareβs area from circleβs area to get the remaining shaded part.
π Trick:
“Break complex shapes into smaller known shapes!”
π Word Problems (With Solutions!)
πΉ Example 1: Find the Perimeter of a Triangle
A triangle has sides 5 cm, 7 cm, and 9 cm. Find its perimeter.
β Solution:
P=5+7+9=21 cm
πΉ Example 2: Find the Area of a Circle
A circular park has a radius of 10 m. Find its area.
β Solution:
A=Οr^2=3.14Γ10^2=314 m^2
π₯ Smart Tricks to Remember Formulas!
π Story Method:
Imagine you have a chocolate bar π«
β If you measure the wrapperβs border, itβs perimeter.
β If you measure the whole chocolate inside, itβs area.
π Shortcut for Exams:
β Square: Multiply side Γ side
β Rectangle: Multiply length Γ breadth
β Triangle: Half of base Γ height
β Circle:
β Circumference: 2Οr
β Area: Οr^2
π Challenge Questions!
1οΈβ£ A rectangular garden is 15 m long and 10 m wide. Find:
β Perimeter
β Area
2οΈβ£ A circular pizza has a radius of 7 cm. Find:
β Circumference
β Area
3οΈβ£ A square park has a side of 20 m. A path of 2 m width runs along the border. Find:
β The area of the park
β The area of the path
π Summary & Key Takeaways
β Perimeter = Total boundary length
β Area = Total surface covered
β Use formulas for different shapes
β Break complex shapes into smaller ones
β Real-life applications: Fencing, painting, flooring, running tracks!
Β
PERIMETER & AREA β 50 MCQs
πΉ Questions (1β50)
- What does perimeter measure?
A) Space inside
B) Boundary length
C) Volume
D) Height - Area measures:
A) Boundary
B) Space inside
C) Length only
D) Height - Perimeter of a square =
A) sideΒ²
B) 2 Γ side
C) 4 Γ side
D) sideΒ³ - Area of a square =
A) 2 Γ side
B) sideΒ²
C) 4 Γ side
D) sideΒ³ - Perimeter of a rectangle =
A) l Γ b
B) 2(l + b)
C) lΒ²
D) bΒ² - Area of rectangle =
A) l + b
B) 2(l + b)
C) l Γ b
D) lΒ² - Unit of perimeter is:
A) cmΒ²
B) cm
C) mΒ²
D) none - Unit of area is:
A) cm
B) m
C) cmΒ²
D) km - Perimeter of triangle =
A) a + b + c
B) a Γ b Γ c
C) aΒ²
D) 2a - Area of triangle =
A) b Γ h
B) Β½ Γ b Γ h
C) b + h
D) hΒ² - Perimeter of square with side 6 cm =
A) 12 cm
B) 24 cm
C) 36 cm
D) 18 cm - Area of square with side 5 cm =
A) 10 cmΒ²
B) 20 cmΒ²
C) 25 cmΒ²
D) 30 cmΒ² - Perimeter of rectangle (l=8, b=4) =
A) 12 cm
B) 24 cm
C) 32 cm
D) 16 cm - Area of rectangle (7 Γ 3) =
A) 21 cmΒ²
B) 14 cmΒ²
C) 10 cmΒ²
D) 24 cmΒ² - Perimeter of triangle (3, 4, 5) =
A) 10
B) 11
C) 12
D) 13 - Area of triangle (b=10, h=6) =
A) 60
B) 30
C) 20
D) 50 - Circumference of circle formula =
A) ΟrΒ²
B) 2Οr
C) rΒ²
D) Οr - Area of circle formula =
A) 2Οr
B) ΟrΒ²
C) rΒ²
D) Οd - Circumference when r=7 cm =
A) 44 cm
B) 49 cm
C) 22 cm
D) 14 cm - Area when r=5 cm =
A) 78.5
B) 50
C) 25
D) 100 - If side doubles, area becomes:
A) Double
B) Half
C) Four times
D) Same - If side doubles, perimeter becomes:
A) Double
B) Four times
C) Half
D) Same - Area of square = 64 cmΒ², side =
A) 6
B) 7
C) 8
D) 9 - Perimeter of square with side 9 cm =
A) 18
B) 36
C) 27
D) 45 - Area of rectangle (l=10, b=2) =
A) 12
B) 20
C) 24
D) 30 - Fence length required =
A) Area
B) Perimeter
C) Volume
D) Height - Paint needed depends on:
A) Perimeter
B) Area
C) Length
D) Width - Tiles required depends on:
A) Area
B) Perimeter
C) Height
D) Length - Running track distance =
A) Area
B) Perimeter
C) Height
D) Radius - Carpet needed for room =
A) Area
B) Perimeter
C) Length
D) Height - Boundary of garden =
A) Area
B) Perimeter
C) Height
D) Volume - Floor covering requires:
A) Perimeter
B) Area
C) Length
D) Width - Painting wall uses:
A) Perimeter
B) Area
C) Length
D) Height - Wire needed for boundary =
A) Area
B) Perimeter
C) Volume
D) Height - Book cover surface =
A) Area
B) Perimeter
C) Volume
D) Height - Shape with equal sides =
A) Rectangle
B) Square
C) Triangle
D) Circle - Formula for triangle area depends on:
A) Side only
B) Base & height
C) Radius
D) Diameter - Circle has:
A) Sides
B) Corners
C) Radius
D) Length - Ο value approx =
A) 2.14
B) 3.14
C) 4.14
D) 1.14 - Diameter =
A) r/2
B) 2r
C) rΒ²
D) Οr - Area of square side 12 =
A) 144
B) 24
C) 36
D) 48 - Perimeter of rectangle (5,3) =
A) 15
B) 16
C) 14
D) 12 - Area of triangle (b=8, h=5) =
A) 40
B) 20
C) 30
D) 25 - Circumference if diameter 14 =
A) 44
B) 22
C) 28
D) 14 - Area increases when:
A) Side increases
B) Side decreases
C) Nothing changes
D) Divide side - Perimeter depends on:
A) Boundary
B) Space
C) Volume
D) Height - Area depends on:
A) Boundary
B) Space inside
C) Height only
D) Length only - Composite shapes are:
A) Single shapes
B) Combined shapes
C) Only circles
D) Only squares - To solve complex shapes:
A) Ignore
B) Break into parts
C) Guess
D) Multiply - Best way to remember formulas:
A) Ignore
B) Practice
C) Memorize without use
D) Skip
β ANSWER KEY
1-B, 2-B, 3-C, 4-B, 5-B,
6-C, 7-B, 8-C, 9-A, 10-B,
11-B, 12-C, 13-B, 14-A, 15-C,
16-B, 17-B, 18-B, 19-A, 20-A,
21-C, 22-A, 23-C, 24-B, 25-B,
26-B, 27-B, 28-A, 29-B, 30-A,
31-B, 32-B, 33-B, 34-B, 35-A,
36-B, 37-B, 38-C, 39-B, 40-B,
41-A, 42-B, 43-B, 44-A, 45-A,
46-A, 47-B, 48-B, 49-B, 50-B
